Webb12 apr. 2024 · Solution:-. Create a stack. Split the path by '/'. Filter out the empty strings and '.' using filter function and store the result in a list. Iterate over the list and if the element … Webb5 sep. 2024 · public class Solution { public String simplifyPath(String path) { String result = ""; String[] pathList = path.split("/"); if (pathList.length == 0) { return "/"; } Stack stack = new Stack<>(); for (String p : pathList) { if ("".equals(p) ".".equals(p)) { continue; } if ("..".equals(p)) { if (!stack.isEmpty()) { stack.pop(); } } else { // …
71. Simplify Path · leetcode
Webb5 feb. 2024 · This is part of a series of Leetcode solution explanations (index). If you liked this solution or fou... Tagged with algorithms, javascript, ... Simplify Path 14 Solution: … WebbIn this post, you will find the solution for the Simplify Path in C++, Java & Python-LeetCode problem. We are providing the correct and tested solutions to coding problems present … importance of assessment in early years
Simplify Path leetcode daily challenge Leetcode Medium
Webb12 apr. 2024 · Let's solve LeetCode #71 Simplify Path! Timeline0:00 Read the question of Simplify Path1:30 Explain a basic idea to solve Simplify Path4:23 Coding6:56 Time ... Webb13 feb. 2024 · class Solution: def simplifyPath (self, path: str)-> str: # split the path into a list of directories dirs = path. split ('/') # initialize a stack to store the directories stack = [] … WebbHey #connections ! Today is the #day52 of the #100daysofcodechallenge . I solved a question of #leetcode which was "Simplify Path". Question link :… importance of assessments in early years