WebDiastasis recti can be diagnosed by physical examination, which may include measuring the distance between the rectus abdominis muscles at rest and during contraction at several levels along the linea alba.; Abdominal ultrasonography provides objective evidence for the diagnosis, and also confirms that the bulge is not a hernia.; An abdominal CT scan is an … Web4 okt. 2024 · In the given figure, ABC is a right-angled triangle, right-angled at A. Semicircles are drawn on AB, AC and BC as diameters. asked Jan 25, 2024 in Mathematics by Swara ( 80.4k points) areas related to circles
Free SAT Maths Level 1 Subject Solutions with Explanations
WebANSWER: (c) AB > AD AB>AC is given.∴ ∠ACB>∠ABC Now, ∠ADB>∠ACD (exterior angle)⇒∠ADB>∠ACB>∠ABC⇒∠ADB>∠ABD⇒AB>AD Suggest Corrections 12 Similar questions Q. In the given figure, AB > AC. Then which of the following is true? (a) AB < AD (b) AB = AD (c) AB > AD (d) Cannot be determined Q. Web13 feb. 2024 · In the figure above, AC is a diameter of the circle. What is the area of triangle ABC? (1) The area of the circle is 4900 π and the length of BC is 84. (2) The perimeter of triangle ABC is 336 and the length of AB is 4 5 times the length of BC. Show Answer Attachments figure.png [ 2.24 KiB Viewed 5432 times ] L chetan2u Math Expert swansea city podcast
In the Figure, PA, QB and RC are perpendicular to AC. Prove that …
Web11 jul. 2024 · AB + AC + BC = 48 AB + (AB +9) + (AB + 9 + 3) = 48 Solve and AB = 9 So AB = 9, AC = 18 and BC = 21 What is a hectogeneous mixture? a hectogeneous mixture … Web1.5 m 1 m C D 5 m A B. A non-uniform rod AB has length 5 m and weight 200 N. The rod rests horizontally in equilibrium on two smooth supports C and D, where AC = 1.5 m and DB = 1 m, as shown in the diagram above. The centre of mass of AB is x metres from A. A particle of weight W newtons is placed on the rod at A. WebABC is an isosceles triangle with AB = AC and D is a point on BC such that AD ⊥ BC (Figure. To prove that ∠ BAD = ∠ CAD, a student proceeded as follows: In Δ ABD and Δ ACD, AB = AC (Given) ∠ B = ∠ C (because AB = AC) And ∠ ADB = ∠ ADC. Therefore, Δ ABD ≈ Δ ACD ( AAS) So, ∠ BAD = ∠ CAD (CPCT). What is the defect in the above … swansea city plumbing